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The 17th Zhejiang Provincial Collegiate Programming Contest - A - AD 2020

题目

https://codeforces.com/gym/102770/problem/A

思路

大模拟,注意要使用前缀和,否则会T

AC代码

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#include <bits/stdc++.h>
#define endl '\n'
using namespace std;
struct _IO { _IO() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); } }_io;
typedef long long ll; typedef long double ld; typedef pair<ll, ll> pll;

bool leapyear[10005], a_year[10005];
bool is31[13] = { 0,1,0,1,0,1,0,1,1,0,1,0,1 };
ll sum[10005], l_mon[13], n_mon[13];
ll ss(ll x)
{
ll res = 0;
while (x != 0)
{
res *= 10;
res += x % 10;
x /= 10;
}
return res / 10;
}
void init()
{
for (ll i = 2000; i <= 9999; ++i)
{
if (i / 10 == 202 || ss(i) == 202) a_year[i] = 1;
if (i % 400 == 0 || (i % 4 == 0 && i % 100 != 0)) leapyear[i] = 1;
}

for (ll i = 2000; i <= 9999; ++i)
{
if (a_year[i]) sum[i] += leapyear[i] ? 366 : 365;
else
{
if (i % 10 == 2) sum[i] += leapyear[i] ? 29 : 28;
else ++sum[i];
++sum[i];
}
sum[i] += sum[i - 1];
}

for (ll i = 1; i <= 12; ++i)
{
if (i == 2) l_mon[i] = 29;
else if (is31[i]) l_mon[i] = 31;
else l_mon[i] = 30;
l_mon[i] += l_mon[i - 1];
}

for (ll i = 1; i <= 12; ++i)
{
if (i == 2) n_mon[i] = 28;
else if (is31[i]) n_mon[i] = 31;
else n_mon[i] = 30;
n_mon[i] += n_mon[i - 1];
}
}
bool judge(ll m1, ll d1, ll m2, ll d2, ll m, ll d)
{
if (m1 < m && m < m2) return 1;
if (m1 < m && m == m2 && d <= d2) return 1;
if (m1 == m && m < m2 && d >= d1) return 1;
if (m1 == m2 && m1 == m && d1 <= d && d <= d2) return 1;
return 0;
}
ll cul(ll y, ll m1, ll d1, ll m2, ll d2)
{
ll res = 0;
if (m1 < m2)
{
if (leapyear[y]) if (m2 - 1 >= m1) res += l_mon[m2 - 1] - l_mon[m1];
if (!leapyear[y]) if (m2 - 1 >= m1) res += n_mon[m2 - 1] - n_mon[m1];
if (m1 == 2) res += (leapyear[y] ? 29 : 28) - d1 + 1;
else res += (is31[m1] ? 31 : 30) - d1 + 1;
res += d2;
}
else res += d2 - d1 + 1;
return res;
}

int main()
{
init();
ll T;
scanf("%lld", &T);
while (T--)
{
ll y1, m1, d1, y2, m2, d2;
scanf("%lld%lld%lld%lld%lld%lld", &y1, &m1, &d1, &y2, &m2, &d2);

ll ans = 0;
if (y2 - 1 >= y1) ans += sum[y2 - 1] - sum[y1];

if (y1 != y2)
{
if (a_year[y1]) ans += cul(y1, m1, d1, 12, 31);
else
{
if (y1 % 10 == 2)
{
if (m1 < 2) ans += leapyear[y1] ? 29 : 28;
else if (m1 == 2) ans += (leapyear[y1] ? 29 : 28) - d1 + 1;
}
else if (judge(m1, d1, 12, 31, 2, 2)) ++ans;
if (judge(m1, d1, 12, 31, 12, 2)) ++ans;
}

if (a_year[y2]) ans += cul(y2, 1, 1, m2, d2);
else
{
if (y2 % 10 == 2)
{
if (m2 > 2) ans += leapyear[y2] ? 29 : 28;
else if (m2 == 2) ans += d2;
}
else if (judge(1, 1, m2, d2, 2, 2)) ++ans;
if (judge(1, 1, m2, d2, 12, 2)) ++ans;
}
}
else
{
if (a_year[y1]) ans += cul(y1, m1, d1, m2, d2);
else
{
if (y1 % 10 == 2)
{
if (m1 < 2 && 2 < m2) ans += leapyear[y1] ? 29 : 28;
else if (m1 == 2 && m2 > 2) ans += (leapyear[y1] ? 29 : 28) - d1 + 1;
else if (m1 < 2 && m2 == 2) ans += d2;
else if (m1 == m2 && m1 == 2) ans += d2 - d1 + 1;
}
else if (judge(m1, d1, m2, d2, 2, 2)) ++ans;
if (judge(m1, d1, m2, d2, 12, 2)) ++ans;
}
}

cout << ans << endl;
}
return 0;
}